Question

One vertex of a square ABCD is A (-1,1) and the equation of one diagonal of BD is 3 X + y - 8 =0 then what is the value of C

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Answer 1

Answer:

The coordinate of C is (5, 3)

Step-by-step explanation:

Let the coordinates of C are (x', y')

Since AD will be the another diagonal, the mid point of A and D will lie on the diagonal BD

i.e. it will satisfy the equation of BD

The mid point of A and D is (\frac{x'-1}{2}, \frac{y'+1}{2})(

2

x

′

−1

,

2

y

′

+1

)

this will lie on the line 3x + y - 8 = 0

Thus,

3(\frac{x'-1}{2})+\frac{y'+1}{2}=83(

2

x

′

−1

)+

2

y

′

+1

=8

\implies 3x'-3+y'+1=16⟹3x

′

−3+y

′

+1=16

\implies 3x'+y'=18⟹3x

′

+y

′

=18

Step-by-step explanation:

good night dear

Answer 2

hope it's helpful to you.. plz mark as brainlist.....