Question

One way to remove lead ion from water is to add a source of iodide ion so that lead iodide will precipitate out of solution: Pb2+(aq) + 2I-(aq) = PbI2(s).
a. What volume of a 1.0 M KI solution must be added to 100.0 mL of a solution that is 0.15M in Pb2+ ion to precipitate all the lead ion?
b. What mass of PbI2 should precipitate?

Answer 1

Answer:

Explanation:

.320L * 0.22M = 0.070 moles of Pb

So, you will need 0.70 moles of I

x L * 1.0 M = 0.70 moles

Looks like 700 mL needed