Question

One who will answer i will mark him as Brainiest
and people who are sending wrong answer i will report it ​

Answer 1

Answer:

(a). Area = 154 units², Perimeter = 80 units; (b). Area = 119 cm²

Step-by-step explanation:

(a). A = πr² ⇒ $A_{semicircle}$ = πr²/2

A = $\frac{22}{7} 14^2$ = 616 units² and $A_{semicircle}$ = 308 units²

Area of interior semicircle is (22/7)×7² = 154 units²

Area of the shaded region is (308 - 154) = 154 units²

Perimeter of the shaded region is

(Outer circumference)/2 + (Inner circumference)/2 + 14 =

$\frac{22}{7}*14$ + $\frac{22}{7}*7$+ 14 = 80 units.

(b). Diameter of semicircle is the base of triangle. d = AB.

r = AB/2 = (35 × 2) ÷ 5 = 14 cm

A = (22/7)×7² - 35 = 154 - 35 = 119 cm²