Question

. one year ago,
a man 8 times as old as his son
Now his
age
is equal to the aquare of his son's age
find present age ?​

Answer 1

Step-by-step explanation:

let his son's age=x

then, father age=8x

present ages are 8x+1,x+1

according to the question,(x+1)^2=8x+1,

x^2+1+2x=8x+1,

x^2-6x=0,

x^2=6x,

x=6

present age of father and son is 49 and7 years.

Answer 2

Step-by-step explanation:

One year ago -

Let his sons age be "x"

so his fathers age will be "8x"

so after 1 year

fathers age = 8x + 1

son's age = x + 1

Now his age is equal to the square of his son's age

Hence

8x + 1 = ( x+1)²

8x + 1 = x² + 1 + 2x

8x = x²+ 2x      "as the 1's get canceled"

now...x^2 - 6x=0

solving this we get ...x=0 and x = 6 but  

age cant be zero...so..x=6...

age of son is x+1 = 7 years

and age of man be 8x+1= 49