Question

one year ago a man was 3times old as his son,in 5years time his age were exceed twice his sons age by 9years ratio of their present age ?​

Answer 1

Answer:

Answer:

Let,

the present age of a man = x years

the present age of son = y years

According to the conditions,

x - 1 = 4(y - 1)

x - 4y = -3 ...(1)

x + 6 = 2(y + 6) + 9

x - 2y = 15 ....(2)

Subtracting (2) from (1), we get

x = 33 and y = 9

Therefore,

present age of a man = 33 years

present age of son = 9 years