one year ago a man was 5 times old as his son. After six years his age exceeds twice by 3 years. find their present age.
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Answer:
F-1 = 4(S-1), or
F = 4S-3 …(1)
F+6 = 2(S+6) + 9
F = 2S+12+9–6 = 2S+15 …(2)
4S-3 = 2S+15
2S = 18
S = 9 and so F = 33.
The ratio the ages of the father and the son is 33:9, or 11:3, now.
The ratio the ages of the father and the son 6 years later will be 39:15, or 13:5, now
Step-by-step explanation:
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