Question

One year ago a man was 7 times as old as his son if his age was 42 years then the present age of son is

Answer 1

Answer:

Let son age = x

One year ago :

Age of son = x - 1

Age of man = 7(x - 1) = 7x - 7

Now,

Age of man = 42 years.

==> 7x - 7 = 42

==> 7x = 49

==> x = 7

Thus,

Present age of son = 6 years and man = 42 years.