Question

One year ago, a man was 7 times as old as his son. The equation of this situation: (Take : present age
of father and son x and y year respectively)​

Answer 1

Answer:

7(y-1)=x-1

We subtracted 1 to ensure in was a year before.

Answer 2

Answer:

7x-y=6

or

7x-y-6=0

Step-by-step explanation:

Present age,

Son=x

Father=y

One year ago age,

Son=x-1

Father=y-1

According to question

7(x-1)=y-1

7x-7=y-1

7x-y=6

or

7x-y-6=0