Question

one year ago,a man was 8 times as old as his son. now, his age is equal to the square of his son's age . find their present age????

Answer 1

given,
age of son=x
age of man=x²
one year back,
age of son=x-1
age of man=x²-1=8(x-1)
x²-1=8x-8
x²-1+8-8x=0
x²-8x+7=0
x²-7x-x+7=0
x(x-7)-1(x-7)=0
(x-7)(x-1)=0
x=7,1
age of son =7 years