Question

One year ago a man was 8 times as old as his son. Now his age is equal to the square of the age of his son. Find his present age.​

Answer 1

Answer:

Let the present age of the son be x years. It is given that one year ago; a man was 8 times as old as his son. If x = 1, then x2 = 1, which is not possible as father's age cannot be equal to son's age. Present age of man = x2 years = 49 years.

Answer 2

Answer:

Let the present age of the son be x years. ∴ Present age of man = x2 years One year ago, Son's age = (x − 1) years Man's age = (x2 − 1) years It is given that one year ago; a man was 8 times as old as his son. ∴ (x2 − 1) = 8(x − 1) x2 − 8x − 1 + 8 = 0 x2 − 8x + 7 = 0 (x − 7) (x − 1) = 0 x = 7, 1 If x = 1, then x2 = 1, which is not possible as father's age cannot be equal to son's age. Present age of son = x years = 7 years Present age of man = x2 years = 49 years.Read more on Sarthaks.com - https://www.sarthaks.com/147929/one-year-man-was-times-old-his-son-now-age-equal-the-square-his-sons-age-find-their-present-ages