One+year+ago+a+man+was+8+times+as+old+as+his+son.+now+his+age+is+equal+to+the+square+of+his+son'so+age+.find+their+present+age
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Hello guys Namaste,
Let age of son one yr ago be x
age of man one yr ago be 8x
age of son after one year = x+1
age of man after one year = 8x+1
now accordind to question..
8x+1= (x+1)^2
8x+1=x^2 + 1 +2x
after solving
8x = x^2 +2x
now, x^2 - 6x=0
solving this we get x=0 and x = 6 but
age cant be zero.
so, x=6
age of son is x+1 = 7 years
and age of man be 8x+1= 49 Answer.
Let age of son one yr ago be x
age of man one yr ago be 8x
age of son after one year = x+1
age of man after one year = 8x+1
now accordind to question..
8x+1= (x+1)^2
8x+1=x^2 + 1 +2x
after solving
8x = x^2 +2x
now, x^2 - 6x=0
solving this we get x=0 and x = 6 but
age cant be zero.
so, x=6
age of son is x+1 = 7 years
and age of man be 8x+1= 49 Answer.
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