Math, asked by madhuramalpani, 8 months ago

One year ago, aman was 8 times as old as his son. now his age is equal to the square of his son's age. Find their present ages​

Answers

Answered by bhartinikam743
1

I hope you like my answer........

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Answered by ppaass195
1

Answer:

present age of aman be x

x-1 = 8(y-1)-------eq1

x=y^2 -------------eq2

x= 8y -7

8y-7 = y^2

y^2-8y+7 = 0

y^2 -7y-1y +7 =0

y = 7 or 1

x = 49 or 1

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