Question

one year ago, Jaya was four times as old as her daughter, Tannu. six years hence, Jaya's age will exceed her daughter's age by 9 years. find their present ages.

Answer 1

Let Tannu's age 1year ago be x
Jaya's age =4x
After 6 years,
Jaya's age will be 4x+7(because her age was 4 times last year)
Jaya's age = x+7+9
Therefore,
4x+7=x + 16
4x-x= 16-7
3x=11
x= 11/3 =3 years 3 months
So Tannu's present age is 4years 3 months

Answer 2

Jaya = x
Tannu = y
x-1 =4(y-1).
X-1 = 4y-4
X- 4y = -3

X+6 =y + 6 + 9
X- y = 9
X- 4y = -3
3 y = 12;
Y= 4
X = 3
That s it .