Question

One year ago pandit was three times his sisters age. Next year he will be only twice her age. How old will pandit be after five years?

Answer 1

mark it as brainliest

Answer 2

$<b>Heya mate. (^_-). Solution below.$
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• Let Pandit's sister's present age be 'x'.


[] 1 year ago,

Pandit's sister's age = x - 1

Pandit's age = 3(x - 1) = 3x - 3



[] At present,

Pandit's sister's age = x - 1 + 1 = x

Pandit's age = 3x - 3 + 1 = 3x - 2


[] After one year,

Pandit's sister's age = x + 1

Pandit's age = 3x - 2 + 1 = 3x - 1



[] But, according to the question, after one year, Pandit will be twice his sister's age.

=> 3x - 1 = 2(x + 1)

=> 3x - 1 = 2x + 2

=> 3x - 2x = 2 + 1

=> x = 3


[] So, Pandit's sister's present age = x = 3 years.

[] And, Pandit's present age = 3x - 1 = 3 × 3 - 2 = 9 - 2 = 7 years.




[] Now, 5 years after,

Pandit's sister's age = 3 + 5 = 8 years.

Pandit's age = 7 + 5 = 12 years.


$<marquee>Hence, Pandit's age after 5 years would be 12 years.</marquee>$
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Thank you... ;-)