Math, asked by trisha655, 10 months ago

One year ago, the ratio of Harsha's and
Mandar's salaries was 3:5. The ratios of
their individual salaries of last year and present
year are 2 : 3 and 4:5 respectively. If their
combined salary for the present year is
Rs.86,000, find the present salary of Harsha.
(1) Rs.38,000 (2) Rs.24,000
(3) Rs.39,000 (4) Rs.36,000
(5) Rs.28,000​

Answers

Answered by bhagyashreechowdhury
1

Answer:

Given the ratio of Harsha’s salaries, last year and present year is 2 : 3

So, let the salary of Harsha last year be Rs. “2x” and present year be Rs. “3x”

The ratio of Mandar’s salaries, last year and present is 4 : 5

So, let the salary of Mandar last year be Rs. “4y” and present year be Rs. “5y”

Given that, ratio of Harsha’s and Mandar’s salary 1 year ago = 3 : 5

Then, we can write

2x / 4y = 3 / 5

⇒ 10x = 12y

⇒ 5 x = 6 y

y = 5x/6 …… (i)

Also, given in the question,

Their combined salary for the present year is Rs. 86000

3x + 5y = 86000

Substituting the value of y from (i)

⇒ 3x + 5*(5x/6) = 86000

⇒ 18x + 25x = 516000

⇒ 43 x = 516000

x = 12000

And, y = 5 * 12000 / 6 = 10000

Thus, Harsha’s present salary is  

= 3x

= 3 * 12000

= Rs. 36000

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