Question

one year hence, a father's age will be 5 times the age of his son. The product of the present ages of the father and his son is 145. find their present ages

Answer 1

Answer:

Step-by-step explanation:

Age (son)now is x

Age(father) now is 145/x

Age 1 yr hence

Son-x+1

Father-5x+5

Equate father age

145/x +1=5x+5

Multiply through by x

145+x=5x^2 +5x

5x^2+5x-x-145=0

5x^2+4x-145=0

Sum=4

Product =-725

Ans=25,-29

5x^2+25x-29x-145=0

5x(x+5)-29(x+5)=0

(5x-29)(x+5)=0

x=29/5

=5.8 years

Yeah soI guess you got it from there

Please mark as brainliest

Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20