Question

one your ago a man was 8 times as
old as his son now his age is equal to
the square of his son age find the
Presentage age
​

Answer 1

Answer:

Let the present age of the son be x years. It is given that one year ago; a man was 8 times as old as his son. If x = 1, then x2 = 1, which is not possible as father's age cannot be equal to son's age. So, x = 7.

Answer 2

Answer:

son

Step-by-step explanation:

let the son's age = x

father's age 1 year ago = 8 times the son's age one year ago = 8 (x-1) [given]

So, father's present age = 8(x-1)+1= 8x-8+1= 8x-7

Now, Father's present age= 8x-7 = son's age sqr = x²

x²-8x+7= 0

x²+(-7-1)x +(-7×-1)

(x-1) × (x-7) = 0

So, x = 1 or 7

So, the age of son's age= 7

Father's age= 49

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