One zero of a polynomial f(x)= x² + kx + 42 is 7, What is the value of k ?
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Answered by
3
Answer:
given that,
f(x)=x2+kx+42.
if x=7 is the zero of the given polynomial f(x), then f(7)=0.
ie,
=> (7)^2+7k+42=0
=> 49+7k+42=0
=> 91+7k=0
=> 7k=-91
=> k=-91/7
=> k=-13
I hope it would help you
thank you
Answered by
0
Answer:
if 7 is a zero of f(x)
then f(7)=0
7²+7k+42=0
49+42+7k=0
91+7k=0
7k=-91
k=-13 answer
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