Question

One zero of quadratic polynomial 4x2 -8x-5 is 5/2 then the other zero is

Answer 1

Answer:

the other zero is $\frac{-1}{2}$

Step-by-step explanation:

$given \ polynomial,\\ 4x^{2} -8x-5 \\=> it \ is \ of \ the \ form \ ax^{2} +bx+c \\\\a=4,b=-8 \ and \ c=-5 \\\\=> relationship \ between \ zeroes \ of \ the \ polynomial \ is \ given \ by \\ sum \ of \ zeroes =\frac{-b}{a} \\ product \ of \ zeroes = \frac{c}{a} \\\\ =>given,one \ of \ the \ zeroes =\frac{5}{2} \\\\let \ the \ other \ zero \ be \ x. \\\\product \ of \ zeroes =\frac{c}{a} \\\\=> (x)(\frac{5}{2}) =\frac{-5}{4} \\\\=> \frac{5x}{2}=\frac{-5}{4}\\\\=> \frac{x}{2} =\frac{-1}{4}$

$=>x=\frac{-2}{4}\\\\=>x=\frac{-1}{2} \\\\\\the \ other \ zero \ is =\frac{-1}{2} \\\\ HOPE \ IT \ HELPS...!$