Question

One zero of the polynomial 3x + 16x2 + 15x -18 is 2/3 .Find other
zeros of the polynomial.​

Answer 1

Question:

One zero of the polynomial 16x² + 18x -18 is 2/3 .Find other zeroes of the polynomial.

3x + 16x² + 15x -18 = 16x² + 18x -18

To find:

★ To find the other zero of polynomial.

Answer:

$The \: other \: root \: is \: \underline{ \: \sf \pink{\bold{ \frac{ - 43}{24}} } \: }$

Given:

★ An equation is given, 16x² + 18x -18

$\bigstar \: One \: of \: zero = \frac{2}{3}$

Step-by-step explanation:

$16 {x}^{2} + 18x -18 = 0$

$It's \: of \: the \: form,$

$a {x}^{2} + bx + c = 0$

$Here, \: \underline{ a = 16, \: b = 18, \: c = - 18}$

$Let \: one \: root \: be \: \alpha$

$Let \: other \: root \: be \: \beta$

$\boxed{Sum \: of \: roots = \frac{ - b}{a} }$

$\alpha + \beta = \frac{- 18}{16}$

$\implies \frac{2}{3} + \beta = \frac{ - 9}{8}$

$\implies \beta = \frac{ - 9}{8} - \frac{2}{3}$

$\implies \beta = \frac{ - 27 - 16}{24}$

$\implies \boxed{ \beta = \frac{ - 43}{24} }$

$\therefore The \: other \: root \: is \: \underline{ \: \bold{ \frac{ - 43}{24} } \: }$