Question

One zero of the polynomial 3x + 16x2 + 15x - 18 is 2/3. Find the other zero of the polynomial.​

Answer 1

Given

A polynomial 16x²+18x-18

one of zeroes is 2/3

To find

Other Zeroes

Solution

Let the other Zeroes of polynomial be $\alpha$

we know that

$\alpha+\beta=\frac{-b}{a}$

Here a=16

b=18

Now putting the values

$\alpha+\beta=\frac{-b}{a}$

$\alpha+\frac{2}{3}=\frac{-18}{16}$

$\therefore\alpha=-\frac{2}{3}\frac{-18}{16}$

$\therefore\alpha=\frac{-32-54}{48}$

$\therefore\alpha=\frac{-86}{48}$

Hence,other Zeroes be $\rightarrow\frac{-86}{48}$