one zero of the polynomial 3x³+16x²+15x-18 is 2/3 .find the other zero of the polynomial.
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Zeros of of the polynomial f (x ) = -3, -3 , 2/3
Step-by-step explanation:
f(x) = 3x³ + 16 x² + 15 x - 18
x = 2/3
x - 2/3 = 0
3x -2 = 0
If we divide 3x³ + 16 x² + 15 x - 18 by 3x -2
which is shown in picture so kindly check the picture ....
We get , x² + 6x +9 = 0
x² + 3x + 3x + 9 = 0
x (x +3) + 3( x+3) = 0
(x +3)(x+3) = 0
x = -3, -3
Zeros of of the polynomial f (x ) = -3, -3 , 2/3
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