Question

One zero of the polynomial 3x³ + 16x²+ 15x - 8 is 2/3. Find the other zeroes of the polynomial.​

Answer 1

Answer:

Step-by-step explanation:

x=2/3 is one of the zero of the polynomial.

Now,

x=2/3

x-2/3=0

Now on dividing 3x^3+16x^2+15x-18

We will get the quotient x^2+6x+9

q(x)=x^2+6x+8

=x^2+3x+3x+9=0

=x(x+3)+3(x+3)=0

=(x+3)(x+3)=0

x+3=0. x+3=0

x=-3. x=-3

Therefore, its two other zeroes are -3and -3.

Hope it will help you!