Question

One zero of the polynomial 3xcube + 16xsquare +15x - 18 is 2/3. find the other zeros of the polynomial.

Answer 1

it's your answer.....

Answer 2

Answer:

The other two zeroes are -3 and -3.

Step-by-step explanation:

Given one zero of the polynomial $3x^3+16x^2+15x-18$. w have to find the other two zeroes of above.

As, $\frac{2}{3}$ is one of the zero of above polynomial. Hence, by synthetic division done in figure, we get

$3x^3+16x^2+15x-18=(x-\frac{2}{3})(3x^2+18x+27)$

To find zeroes

$3x^3+16x^2+15x-18=(x-\frac{2}{3})(3x^2+18x+27)=0$

⇒ $(3x^2+18x+27)=0$

⇒ $x^2+6x+9=0$

⇒ $x^2+3x+3x+9=0$

⇒ $x(x+3)+3(x+3)=0$

⇒ $(x+3)(x+3)=0$

⇒ x=-3,-3

Hence, the other two zeroes are -3 and -3.