Question

one zero of the polynomial x²+11x+k is -3 find the value of K and the other zero

Answer 1

Answer:

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Answer 2

$\huge{\underline{\underline{\sf{Answer \colon}}}}$

Let p(x) = x² + 11x + k be the given polynomial

According to the Question,

p(x) = p(- 3) = 0

Implies,

$\sf{p( - 3) = ( - 3){}^{2} + 11( - 3) + k } \\ \\ \implies \: \sf{9 - 33 + k = 0} \\ \\ \implies \: \boxed{ \sf{k = 24}}$

Now,

• The polynomial would be x² + 11x - 24

Let the other zero be y

We know that,

Sum of zeros:

-x coefficient/x² coefficient

$\implies \: \sf{y - 3 = - 11} \\ \\ \implies \: \huge{ \sf{y = - 8}}$

Thus,the zero of the given polynomial are -3 and -8