Question

One zero of the polynomial x2 - 2x - (7p + 3), find the value of p and the other zero.

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Answer 1

Answer:

3

Step-by-step explanation:

Given  

One zero of the polynomial x2 - 2x - (7p + 3), find the value of p and the other zero.

ANSWER  

Given f(x) = x^2 – 2 x – (7 p + 3)

Given one zero of polynomial f(x) = - 4 and other zero be a

So sum of zeroes = coefficient of x / coefficient of x^2

-4 + a = - (- 2)/1

-4 + a = 2

a = 2 + 4 = 6

The other zero is 6

Now product of zeroes = constant term / coefficient of x^2

-4 x 6 = - (7 p + 3) / 1

-24 = - (7 p + 3)

7 p + 3 = 24

7 p = 24 – 3

7 p = 21

P = 3

So the value of p is 3

Answer 2

Answer

$\sf{If -4 \: is \: zero \: of \: given \: polynomial \: then} \\ \\(−4)2−2(−4)−(7p+3)=0 \\ \\ ⇒16+8−7p−3=0 \\ \\ ⇒7p=21 \\ \\ ⇒p=3$