Question

One zero of x2-2x-7p+3 is -4 find the value of p and other zero

Answer 1

let the given playnomial be p(x)
p(x)=x²-2x-7p+3
if -4 is root then p(x) must be zero
p(-4)=(-4)²-2(-4)-7p+3=0
=16+8-7p+3=0
=27-7p=0
=27=7p
=27/7=p
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Answer 2

Answer

$\sf{If -4 \: is \: zero \: of \: given \: polynomial \: then} \\ \\(−4)2−2(−4)−(7p+3)=0 \\ \\ ⇒16+8−7p−3=0 \\ \\ ⇒7p=21 \\ \\ ⇒p=3$