Question

One zeros of x2 + 7x + 12 is x=3, Find is second zeros​

Answer 1

First zero is -3.

second zero is -4.

Step-by-step explanation:

x^2+7x+12=0

(x^2+4x)+(3x+12)=0

x(x+4)+3(x+4)=0

(x+3)(x+4)=0

x+3=0 , x+4=0

x=-3 , x=-4