onents. A batsman hits the shot with initial velocity of 28 m/s. If the boundary is 72m from the batsman, will the ball cross the boundary for six? If the angle with horizontal is 40°. Find out time when ball bounce the ground.
Answers
Answered by
1
Answer:
28 cos of 40
28 cos 0.76
21.46 is the velocity
v^2= u^2+2as
0^2=21^2+2×28s
s=7.85
t=
Similar questions