Question

Ones place digit of a number exceeds its tens digit by
3. Write the two digit number taking x as its ones place digit.​

Answer 1

Answer:

11x + 3

Step-by-step explanation:

Let x be ones digit. (It is also given)

Let y be the tens digit.

Now, it is given that x exceeds y by 3.

So, y = x + 3

A 2 digit no. with x as ones and y as tens digit is 10x + y.

=> 10x + (x + 3)                  (Shown above)

=> 11x + 3

Thus, the general form of a number whose ones digit exceeds its tens digits by 3 is 11x + 3.