ONILY 55% OF THE 42000 ELIGIBLE VOTES IN A CONSITTUENCY CAST THEIR VOTES. OF THE VOTES CASTED "A" RECEIVES 37%. b RECEIVES 43% AND C RECEIVES THE REMINDER/ hOW MANY VOTES DOES C GET? MATH SOLVE
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Answer:
Total votes casted = 55% of 42000 = 23100 votes.
A receives = 37% of 23100 = 8547 votes.
B receives = 43% of 23100 = 9933 votes.
C receives = 23100 - 8547 - 9933
= 4620 votes.
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