Question

onions were packed in sacks each weighing 18kg 500g. How many such sacks can be loaded in a truck with a carrying capacity of 3182kg ?

Answer 1

Given:

The weight of each sack of onions = 18 kg 500 g = (18 + 0.5) kg = 18.5 kg .... (since 1 gram = $\frac{1}{1000}$ kg)

The carrying capacity of the truck = 3182 kg

To find:

No. of sacks of onion that can be loaded in a truck with a carrying capacity of 3182 kg

Solution:

Let "n" be the no. of sacks of onions that can be loaded in the truck.

We will solve the above problem in the following way:

[Total carrying capacity of the truck] = n × [Weight of each sack of onion]

Now, substituting the values, we get,

$3182 = n \times 18.5$

⇒ $n = \frac{3182}{18.5}$

⇒ $\bold{n = 172}$

Thus, 172 such sacks of 18 kg 500 g can be loaded in a truck with a carrying capacity of 3182 kg.

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Answer 2

Answer:

172

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Step-by-step explanation:

Track carring=3,182kg

Number of onion in 1 packet =18kg500g

Total=3182 ÷18500g

=172 packet

so, 172 such sacks can be loaded in a truck.