Question

Only 1 and 2 question

Answer 1

,in quadrilateral ABCD there are two triangles triangle ABD and triangle BCD.
the area of triangle ABD = 1/2×base×height
= 1/2×42×12
= 252m²
the area of triangle BCD = 1/2×base×height
= 1/2×42×9
= 189m²
the arABCD = arABD + arBCD
= 252m²+189m²
= 441m² ans.

2. in quadrilateral ABCD there are two Triangles: triangle ABC and triangle ADC .
the area of ∆ABC = 1/2×base×height
= 1/2×62×20
= 620m²
the area of ∆ADC = 1/2×base×height
= 1/2×54×18
= 486m²
the area of ABCD = ar∆ABC + ar∆ADC
= 620m²+486m²
= 1106m² ans.
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