only by grouping method
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1. abc-ab-c+1
=abc-c-ab+1
=c(ab-1)-1(ab-1)
=(c-1)(ab-1)
2. 4x²+2y²+x²y²+8
=4x²+x²y²+2y²+8
=x²(4+y²)+2(4+y²)
=(x²+2)(4+y²)
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Answer:
1. abc - ab - c + 1
= ab(c - 1) - 1(c - 1)
= (ab - 1) (c - 1)
2. 4x^2 + 2y^2 + x^2y^2 + 8
= (4x^2 + x^2y^2) + (2y^2 + 8)
= x^2(4 + y^2) + 2(y^2 + 4)
= x^2( y^2 + 4) + 2(y^2 + 4)
= (x^2 + 2) (y^2 + 4)
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