Math, asked by zeeshan7869, 7 months ago

only by grouping method​

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Answers

Answered by Anonymous
0

1. abc-ab-c+1

=abc-c-ab+1

=c(ab-1)-1(ab-1)

=(c-1)(ab-1)

2. 4x²+2y²+x²y²+8

=4x²+x²y²+2y²+8

=x²(4+y²)+2(4+y²)

=(x²+2)(4+y²)

Answered by pushpabajnikathayat3
0

Answer:

1. abc - ab - c + 1

= ab(c - 1) - 1(c - 1)

= (ab - 1) (c - 1)

2. 4x^2 + 2y^2 + x^2y^2 + 8

= (4x^2 + x^2y^2) + (2y^2 + 8)

= x^2(4 + y^2) + 2(y^2 + 4)

= x^2( y^2 + 4) + 2(y^2 + 4)

= (x^2 + 2) (y^2 + 4)

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