Question

Only by substitution method only.. ...........
Solve the following pairs of equations by reducing them to a pair of linear equations:

Answer 1

Hey Mate ✌

↪ Here's your answer friend,

Let 1 / x - 1 be m

and 1 / y - 2 be n

==> we get,

5m + n = 2 ...........(1)

6m - 3n = 1 ...........(2)

==> From eq(1) we get,

y = 2 - 5m....... (3)

Now on substituting eq(3) in eq(2)

we get,

6m -3n = 1

==> 6m - 3 (2 - 5m) = 1

==> 6m -6 + 15m = 1

==> 21m = 7

⏩ m = 1/3

and now by substituting m = 1/3 in eq(1) we get,

5m + n = 2

5 (1/3 ) + n = 2

5/3 + n = 2

⏩n = 1/3

But m = 1/ x - 1

1/ 3 = 1 / x - 1

==> x - 1 = 3

⏩ x = 4

and n = 1 / y - 2

we get,

1/3 = 1/y-2

y - 2 = 3

⏩ y = 5

⭐ HOPE IT HELPS YOU ^_^ ⭐