Question

ONLY FOR GENIUS...!!!


the angle of elevation of the top of a vertical tower from a point on the ground is 60° from another point 10m vertically above the first its angle of elevation is 45° find the height of the toweR​

Answer 1

Let height of tower = x + 10m

let dist. between base of tower and obs. pt. = y

at first angle it makes with ground = 60 degree

tan(60) = sqrt{3} = (x + 10)/y . . . . . . (eq 1)

next angle = 45 degree

pt is 10 m above the ground

tan(45)= 1 = x/y

:. x=y . . . . . . . . . (eq. 2)

substituting value of y in eq. 1

x + 10 = 1.732 x

:. x = 13.66 m