Question

Only for geniuses!!!!
The numerator of afraction is three less than its denominator. If two is added to both the numerator and denominator the sum of the new fraction and the original fraction is 29/20.Find the original fraction?

Answer 1

29/20 is the fraction

Answer 2

$\huge\textbf{Answer}$

(x-3)/x=7/10

Step-by-step explanation:

Let the denominator be x

So, Numerator is x-3

We got fraction,

\frac{x}{x-3}

x−3

x

According to question, when 2 is added to numerator and denominator,

Then, we get = (x-1)/(x+2)

So,

=> (x-3)/x +(x-1)/(x+2)= 29/20

=> (x-3)((x+2) +x(x-1)

=> x(x+2)*29/20

⇒ (x²-6-x + x²-x)20= 29x²+58x

⇒ 40x²-120-40x=29x²+58x

⇒ 11x²-98x- 120=0

⇒ 11x² - 110x +12x -120=0

⇒ (11x+12)(x-10)=0

We will have to cancel the negative fraction value of x.

=> X = 10

We have the fraction,

=> (x-3)/x=7/10