Science, asked by Anonymous, 9 months ago

only for Moderators

#moderators_challenge

Three resistance 10,3 and 6 are connected what is the Potential difference across 10 ohms resistance.

Note :- It is not given, that it is connected in parallel or series..
$<marquee behavior="alternate">◾️ Answer, if you are 100% sure◾️</marquee>$

$<marquee behavior="alternate">◾️[tex]\huge\red{\mathfrak{No \: SPAM}}$ ◾️</marquee>[/tex]

Answers

Answered by Anonymous

Answer:

• For parallel Combination, Potential Difference, across 10 ohm resistor = V = 10 × I(1) Volts = V(2) = V(3) = V(1)

• For series combination, Potential Difference across 10 ohm resistor = V(1) = 10 × I Volts

Explanation:

NOTE : THE EXPLANATION IS GIVEN IN THE ATTACHMENT BELOW. KINDLY REFER TO THAT IN ORDER.

'A piece of Supplementary Counsel' :-

• About Value of Potential Difference =

We know that,

By ohm's Law,

Resistance = Voltage / Current

=> 1 ohm = 1 Volt / 1 Ampere

=> Volt = ohm × Ampere

=> V = R × I

• About Series Combination of Resistors = A circuit is said to be connected in series when the same amount of current flows through the resistors. In such circuits, the voltage across each resistor is different. In a series connection, if any resistor is broken or a fault occurs, then the entire circuit is turned off. In series combination, current remains same at each component while the potential difference gets divided within the components.

I = I1 = I2 = I3

V = V1 + V2 + V3

R(eq) = R1 + R2 + R3

• About Parallel Combination of Resistors = A circuit is said to be connected in parallel when the voltage is same across the resistors. In such circuits, the current is branched out and recombines when branches meet at a common point. A resistor or any other component can be connected or disconnected easily without affecting other elements in a parallel circuit. In parallel combination, the current gets divided within the components while the potential difference remains same at each component.

I = I1 + I2 + I3

V = V1 = V2 = V3

1/R(eq) = 1/R1 + 1/R2 + 1/R3

Attachments:

Answered by asritadevi2344

\red {\bf{law \ of \ constant\ proportion} }law of constant proportion\red {\bf{law \ of \ constant\ proportion} }law of constant proportion\red {\bf{law \ of \ constant\ proportion} }law of constant proportion\red {\bf{law \ of \ constant\ proportion} }law of constant proportion\red {\bf{law \ of \ constant\ proportion} }law of constant proportionanswer:
option (c)

additional information:
the rate of
a small flowerless green plant of the division bryophyta, which comprises the mosses and liverworts.

hope it helps❣️you and I am Josie and
..

.
.

$<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$ $<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$ $<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$ $<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$ $<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$ $<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$ $<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$ $<br /><br /><html><br /><br /><body><br /><br /><svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,19<svg height="210" width="500"><br /><br /> <polygon points="100,10 40,198 190,78 10,78 160,198" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/>8" style="fill:lime;stroke:purple;stroke-width:5;fill-rule:nonzero;"/><br /><br /></svg><br /><br />$

Previous Question

Next Question

only for Moderators#moderators_challengeThree resistance 10,3 and 6 are connected what is the Potential difference across 10 ohms resistance.Note :- It is not given, that it is connected in parallel or series..◾️</marquee>[/tex]​

Answers