Question

(Only for mods and stars )

need well explained answer

1000 persons took a dip simultaneously in a rectangular tank which is 80 m long and 50 m broad . What is the rise in the level of warer in the tank if the average displacement of water by a person is 0.04 m³ ? ​

Answer 1

Answer:

Volume of rectangular tank =l×b×h

=80×50×h=4000hm

3

(where 'h' is height of tank)

Average displacement of water by a person

=0.04m

3

∴ Average displace of water by 500 person =0.4×500=20m

3

Rise in water tank ⇒4000h=20

⇒h=

200

1

⇒h=.005m

⇒h=.005×100cm=0.5cm

Step-by-step explanation:

I am sorry for answering this question while I am not an star and a moderator

but this answers is correct as well as

Answer 2

Answer:

the volume of one person = 0.04 m³, be cause when the person takes a dip in the tank, the amount of water displaced is equal to the volume of the person.

500 people take dip at the same time, then water displaced = 500 * 0.04 = 20 m³

the water rises inside the tank of the area of 80 m * 50 m = 4000 m².

The height to which water rises = volume / area = 20/ 4000 = 1/200 m =0.005 m

= 5 millimeters

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