Question

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The base and height of triangle are in ratio 2:3. Its area is 300 cm². Find the height and base​

Answer 1

Answer:

ham bi kr skte hai bhai

its da_mn easy

let the base and height be 2x and 3x

ar of triangle=1/2*b*h

300=1/2*2x*3x

300*2=6x^2

x^2=600/6

x^2=100

x=10

hence,base=20cm

height=30 cm

hope it helps dear

if found helpful mark it as brainiliest and follow m.e

Answer 2

Answer:

Base of the triangle = 20 cm

Height of the triangle = 30 cm

Step-by-step explanation:

Given :

Base and height of the triangle are in ratio = 2:3

Area of the triangle = 300 cm²

To find :

The base and height of the triangle

Taken :

Let the base be 2x

Let the height be 3x

To find the base and height use this formula -:

$\boxed{\sf{{300cm}^{2}=\dfrac{1}{2}\times2x\times3x}}$

After that multiply the value of x with the ratio to find the base and height .

Solution :

$:\implies\sf{{300cm}^{2}=\dfrac{1}{2}\times2x\times3x}$

Use cross multiplication

$:\implies\sf{{300cm}^{2}\times2=2x\times3x}$

$:\implies\sf{{600cm}^{2}=2x\times3x}$

$:\implies\sf{{600cm}^{2}={6x}^{2}}$

$:\implies\sf{\cancel{\dfrac{{600cm}^{2}}{6}}={x}^{2}}$

$:\implies\sf{\sqrt{100}=x}$

$:\implies\sf{10cm=x}$

So , the value of x is 10 cm .

Base -:

$:\implies\sf{10cm\times 2}$

$:\implies\sf{20cm}$

Height -:

$:\implies\sf{10cm\times3}$

$:\implies\sf{30cm}$