Question

only for my first following


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ABCD is a parallelogram, and AE and CF bisect ∠A and ∠C respectively. Prove that AE∥FC. Hint: In this given question, we can use the concept of transversal on two lines in order to solve it and get the required proof. ... As these are equal corresponding angles, the two line segments, AE and FC, are parallel.​

Answer 1

Answer:

Length of pole is XY=15 m

Shadow of pole is =YZ=5

3

angle of elevation of sun with ground is ϕ as shown in figure.

Here in a right angled triangle,

tan(90

∘

−ϕ)=

XY

YZ

=

15

5

3

=

3

1

⇒tan(90

∘

−ϕ)=

3

1

⇒90

∘

−ϕ=60

∘

⇒ϕ=30

∘

Elevation is 30

∘

baadh mein aau

Answer 2

Answer:

please refer to attachment above✌✌