Physics, asked by Anonymous, 10 months ago

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Ans is 1 seonds.

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Answered by Anonymous

Aloha User!

Refer to the attachment for the diagram!

Let t1 and t2 are the timings taken by shots 1 and 2 in reaching point P

So, we use ..

x = ut2 = ucos60° * t1

So, t1 = 2t2....(1)

Now, -y = u*Sin60° * t1 - 1/2g(t1)^2 = -1/2g(t2)^2

-1/2g*(t2)^2 = u*√3/2(2t2) - 1/2g(2t2)^2

t2 = 2√3*5√3/30 = 1 seconds.

So, using eq(1) we get..

t1 = 2 seconds

So, the time interval between firing of shots will be..

∆t = t1 - t2 = 2-1 = 1 seond

So, the answer is 1 second.

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Answered by Anonymous

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