Question

Only for talented one...!!!!

Answer 1

Let's Look The Forces On Block 2M

One Downward Force is 2Mg

One Tension in Pulling Direction

And Acceleration is in the direction of 2Mg because it is higher mass than The Block of Mass M

So The Required Equation Will Be,

2Mg - T = 2Ma ___(1)

Now For Block M

One Tension Only because it is neither going downward or upward.. Hence No Mg and No N

So the Required Equation Will be

T = Ma____ (2)

Adding 1 and 2

2Mg = 2Ma + Ma

2Mg = 3Ma

2g/3 = a

So Acceleration is 2g/3

[Sorry For Bad FBD :P]

Answer 2

For block 2M

2Mg - T = 2MA
T = 2M (g - A)

For block M

T = M ( A - a)

Now equate T

2g - 2A = A - a
A = 2g+a/3

For block 5M

2T - T - 2Ma = 5Ma
T = 7 Ma

7Ma = M ( 2g +a/3 - a)
7a = 2g - 2a/3
21 a +2a = 2g
a = 2/23g

a =2/23 g