Question

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a two digit number is 4 times the sum of digits if is also equal to 3 times the product of digits find the number??

step by step explanation...

Answer 1

Let the unit digit be x and ten's digit be y..
Then, the number becomes = 10y + x

According to the question,

4( x + y ) = ( 10y + x ) ---> ( i )

3 ( xy ) = 10y + x ---> ( ii )

Solving Eqn i,

4x + 4y = 10y + x

4x - x = 10y - 4y

3x = 6y

x = 2y ---> ( a )

Putting value of x in Eqn ii,

3xy = 10y + x

3 ( 2y) y = 10y + 2y

6y^2 = 12y

12y = 6y^2

0 = 6y^2 - 12y

0 = 6y( y - 2 )

0 = y - 2

y = 2

Putting value of y in x,

x = 2y = 2 × 2 = 4

Number = 10y + x = 10( 2) + 4

Number = 20 + 4 = 24

Answer 2

Answer:

Let the unit digit and tens digit of the two digit number be x and y respectively. Number = 10y + x = 10 × 2 + 4 = 24. Hence, the required number is 24