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Explanation:
m1u1+m2u2=-m3V3+m4v4
law of conservation of momentum
0.06x0+5x0=-5xv3 +0.06x500
0=-5v3 + 30
30=5v3
V3=6m/s
the recoil velocity is 6m/s
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Answer:
Therefore the velocity of recoil.
According to law of conservation of momentum is
6 m/s
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