Only Genius Answer it !!! ( 30 Points )
IS THERE NO ONE TO ANSWER IT IN BRAINLY
For a first order reaction A-----> B+C carried out 27 C . If 3.8 X 10^-16 % of the reactant molecules exist in the activated state , The Ea ( activation energy) of the reaction will be ?
The quickest and correct will be marked brainliest !!!
Answers
Answered by
2
I got answer as 1.0×10²kj/mol
MuskanTudu:
add the process also
ok
thq
Consider the limit as Ea→0.
Ea→0Ae−Ea/RT=A=k
Thus, in this condition, the rate constant is equal to the frequency factor if the activation energy is zero. In that condition, 100% of the molecules are "activated" and the reaction proceeds infinitely fast, i.e. A is the limiting rate constant for having 100% activated molecules.
Ea→0Ae−Ea/RT=A=k
Thus, in this condition, the rate constant is equal to the frequency factor if the activation energy is zero. In that condition, 100% of the molecules are "activated" and the reaction proceeds infinitely fast, i.e. A is the limiting rate constant for having 100% activated molecules.
Thus, kA×100% is the percent of molecules that can do the reaction.
kA×100%=3.8×10−16%
⇒kA=3.8×10−18=e−Ea/RT
This means
Ea=−RTln(3.8×10−18)
=−8.314472 J/mol⋅K⋅(27+273.15 K)⋅ln(3.8×10−18)
= 100102 J/mol
= 100.102 kJ/mol
kA×100%=3.8×10−16%
⇒kA=3.8×10−18=e−Ea/RT
This means
Ea=−RTln(3.8×10−18)
=−8.314472 J/mol⋅K⋅(27+273.15 K)⋅ln(3.8×10−18)
= 100102 J/mol
= 100.102 kJ/mol
thank u
i hope this is helpful
can u mark me as brainlist
Answered by
4
Explanation:
So, the species is tetrahedral with sp3 hybridisation. So, the species is linear with sp hybridisation.
Similar questions