Question

only genius can do this now

A 1800 kg car accelerate over a distance of 120m due to the net force of 4200N. If its initial speed was 40 km/h, what is its final speed?​

Answer 1

Answer:

Force =mass×acceleration

F=m×a

a=F/m

=4200/1800

=7/3m/s^2

•Given:-

initial velocity (u)= 40km/h

=40*5/18

=100/9 m/s

final velocity =?

use 3rd equation of motion..

${v}^{2} = {u}^{2} + 2as \\ {v}^{2} = { \frac{(100}{9}) }^{2} + 2 \times \frac{7}{3} \times 120 \\ {v}^{2} = \frac{10000}{81} + 560 \\ {v}^{2} = \frac{55360}{81} \\ v = 235.2 \div 9 \\ v = 26m {s}^{ - 1}$

hope it helps!

Answer 2

Answer: the answer in

Explanation: