Question

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find the equation of the line that is perpendicular to the line x -2y+3=0 and passing through the point(1,-2) ??????

Answer 1

✨✨✨✨ Heya ✨✨✨✨

Given,

line x -2y+3=0

➡
$y = \frac{1}{2} x + \frac{3}{2}$
Slope of line is M1 .

•°• , the slope of the line perpendicular to line one is..

$M_2 =$$- \frac{1}{m1} = - 2$
equation of the line with slope -2 and passing through the point( 1 ,- 2 )is

y -(-2) = -2(x-1) or

y= 2-x
so you get the answer..y = 2- x.