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Since angle b=90
So by Pythagoras Therom
In triangle ABC
AC*2=ab*2+BC*2
So let the common factor of ab&BC be so
(25)*2=3x*2+4x*2
625=x*2(9+16)
25=x*2
x=5
So other two side's are 15&20
Area if triangle ABC=1/2×20×15
Area of triangle ABC=150
in traingle acd area=√s(s-a)(s-b)(s-c)
So area=√70(70-63)(70-52)(70-25)
Area=√70(7)(18)(45)
Area=7(√8100
Area=630
So total area =630+150cm*2=780cm*2
So by Pythagoras Therom
In triangle ABC
AC*2=ab*2+BC*2
So let the common factor of ab&BC be so
(25)*2=3x*2+4x*2
625=x*2(9+16)
25=x*2
x=5
So other two side's are 15&20
Area if triangle ABC=1/2×20×15
Area of triangle ABC=150
in traingle acd area=√s(s-a)(s-b)(s-c)
So area=√70(70-63)(70-52)(70-25)
Area=√70(7)(18)(45)
Area=7(√8100
Area=630
So total area =630+150cm*2=780cm*2
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