Question

⭐⭐ONLY GENUINE ANSWER⭐⭐

find ū at hole.

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Answer 1

ρ = Density of the liquid

A = Area of cross section ( hole )

P = 1 atm

P₀ = Liquid pressure

By equation of continuity,

A₁ v₁ = A₂ v₂

v₂ = A₁ v₁  / A₂

As A₂ >> A₁ 

v₂ ( ū ₁ ) = 0

Applying Bernoulli's Equation,

P₀ + ½ ρ v₁ ² + ρ g( h₂ - h₁ ) + ( P - P₀)

If we take h₂ - h₁  = h, then

½ ρ v₁ ² = ρgh + ( P₀- P )

v₁ ( ū ) = √ 2gh + [ 2 ( P₀ - P) / ρ ]

=> v₁ ( ū ) = √ 2gh + [ 2 P₀ / ρ ] { ∴ P = 1 atm }

If the container is open, then

v₁ ( ū ) = √ 2gP₀ / ρ